I'm very sorry this post came late. I was very busy. I'm sorry.
Note that wat you are going to see right now is not the 2012 NECO
question but most likely question. This is been set with the specimen
given to schools.
But i'm sure 90% of wat you about to see is comming out.
Group 1
ReplyDeleteA-RAT
B-SPIDER
C-SPIDER
D-SNAIL
E-WEEVIL
Group 2
F-MARGARINE
G-GLUCOSE SOLUTION
H-SUCROSE SOLUTION
I-EGG ALBUMEN
Group 3
J-MOLAR TOOTH
K-INCISOR
L-CANINE
Group 4
M-DRY POD OF PRIDE OF BARBADOS
N-GUAVA FRUIT
O-ORANGE FRUIT
P-MANGO FRUIT
Q-DRY OKRO FRUIT
REAGENTS/SOLUTIONS
R-BENEDICTS SOLUTION
S-IODINE SOLUTION
T-MILLIONS REAGENT
U-DILUTE HCC
QUESTION AND ANSWER
ReplyDelete1.
(A) Identify specimens a,b,c,d and e without reasons
(B) State the classes and the phyla of specimens a, b, c, d and e
(C) State five characteristic features each of specimens a, b, c, d and e
(D) (i) State the excretory and respiratory organ of the specimens
(ii) state the economic importance of each of the specimens.
ANSWER
ReplyDeleteSpecimens A is a rat (Rattus rattus)
B is an earth worm (lumbricus terrestis)
C is a spider (lycosa)
D is a snail (archachatina marginata)
E is a weevil (sitophilus sp)
B- specimens class phylum
A Mammalia Chordata
B Oligochaeta Annelida
C Arachnida Athrepoda
D Gastropoda Mollusca
E Insecta Arthropoda
Ci. Five characteristic features of Sp. A are:
- Possession of four body divisions, namely: the head, neck, trunk and tail.
- It is a vertebrate animal
- It has furs on its skin/body
- Has two external ears called pinnae.
- Has well developed sense organs and brain.
- Has a bilateral symmetry.
ii. Five characteristic features of Sp. B are:
- Has a glandular swelling structure called clitellum
- Has a metamerically segmented body
- Has hydrostatic skeleton
- Its body is elongated, narrow and cylindrical in shape.
- Has a bilateral symmetry
- It is hermaphrodite
- Has no eyes and ears
iii. Five characteristic features of Sp. C are:
- Has two body division, namely; the cephalothorax and abdomen
- Has four pairs of walking legs
- Has pedipalps and chelicerae
- Lacks antennae
- Has chitinous exoskeleton called cuticle
- Has jointed appendages
- Has a segmented body
-
v. Five characteristic features of Sp. E are:
- Has three body divisions, namely; the head, thorax and abdomen.
- has jointed appendages
- has segmented body
- its fore wings are modified into elytra
- has a pair of antennae
- has three pairs of walking legs
- Has mouth parts modified to form rostrum
- Has a pair of compound eyes
di.
Specimen Excretory Organ Respiratory Organ
A Kidney Lung
B Nephridium Body surface
C Silk gland Lung – book
D Kidney Ctenidium(gill)
E Malpighiam tubule Trachea
ii. Economic importance of Sp. A
- It can be reared for domestic purposes and as a source of income.
- It is also used as a biological and medical specimen
Economic importance of Sp. B
- It makes the soil fertile through burrowing, aeration, and decomposition of plan remains
- It also prevents the soil from becoming muddy or water logged.
Economic importance of Sp. C
- It is useful to man as it feeds on various insect pests.
- It can serve as a disease vector due to its hairy body which carry germs
Economic importance of Sp. D
- It causes great damage to crops and garden plants
- It serves as a food for man
- It is useful for some domestic medicinal purposes
Economic importance of Sp. E
_ it destroys and eats up storge crops like beans, maize and rice
- It reduces the quality and quantity of grains stored
2a. Carry out the following tests given in the table below. Record your observations and conclusions in the format of the table given below.
ReplyDeletei.
TEST Add a few drops of solution S on specimen F on a white filter paper
OBSERVATION No visible reaction
CONCLUSION F is not starch
ii.
TEST Rub specimen F on a white filter paper and hold the paper against the light
OBSERVATION Translucent property observed
CONCLUSION F is a fat or oil
iii.
TEST Specimen G in a test tube + solution R
OBSERVATION Orange precipitate formed
CONCLUSION G is simple reducing sugar
iv.
TEST Part of Specimen H in a test tube + solution R
OBSERVATION No visible reaction or No effect
CONCLUSION H is a non-reducing sugar
v.
TEST Remaining part of Specimen H in a test tube + solution U + heat + solution R
OBSERVATION Orange or bricked ppt is formed after adding solution R
CONCLUSION It is non-reducing sugar
vi.
TEST Specimen I in a test tube + solution T + boiling
OBSERVATION Brick – red ppt formed
CONCLUSION I is a protein
B
From the test carried out in 2a Identify the following:
Specimen F - margarine Solution
Specimen G - Glucose Solution
Specimen H - Sucrose Solution
Specimen I - Egg Abdomen
Solution R - Benedict Solution
Solution S - Iodine Solution
Solution T - Million’s reagent
Solution U - Dillute HCl
c. State two functions of each of specimens F, G, H, & I
i. Two functions of specimen F
- Provides energy from the body – protects the delicate organs in the body.
- Helps in the cell membrane formation
ii. Two functions of specimen G and H
- Provided energy for the body
- Help in the formation of protein, lipid etc in the body
- Excess is stored in the form of glucogen which serve as an energy reserve in the body
iii. Two functions of specimen I
- For the formation of enzymes and antibodies
- For repairing damaged or worn-out tissues
- For energy source in the body
QUESTION 3
ReplyDelete• identify specimens j, k and l with two reasons each
• state the functions of the specimens in mammals
• what type of dentition does the specimens belong
• which of the specimens is absent in herbivores
• make a well labeled drawing of about 8-10cm in size of specimens j
ANSWER
J is a molar tooth
Reasons
Has cusps on the apical region
Has 3 roots at the basal region
Is broad and tough with a slight elongation.
K is an incisor
Reasons
Has a chisel- like shape
Is elongated/ long in nature/size
Has a broad flat apical region
L is a canine
Reasons
Is less elongated than an incisor
Has a pointed and well shaped aped
(B)
Specimen’s j helps to grind and crush food particles
Specimen’s k is for cutting any food particle in mammals
Specimens l is for tearing flesh
Specimens l is commonly called dog tooth
(C)
Heterodant dentition
Specimens l ( the space/ gap in which the specimens is labeled in herbivores is called diastema)
4 QUESTION
ReplyDelete(a) Identify specimen’s m, n, o, p and q without reasons.
(b) Classify the specimens under the following headings:
• Dehiscent or indehiscent
• Fruit type
• Edible or non edible
• Mode of propagation
• Placentation type
• Botanical / scientific name
(C) state the mode of dispersal, giving one reason each for specimens m, n, o, p and q
(D) name five conditions that are likely to favour the propagation of the specimens
(E) make a well labeled drawing of the transverse / longitudinal
ANSWER
(4) (a) M is a pods of pride of Barbados.
N is a guava fruit
O is an orange fruit
P is a mango fruit
Q is a dry okra fruit
(B)
Heading sp.m sp.n sp.o sp.p sp.q
(i) delriscent or
Non-dehiscent indeliscent dehiscent indehiscent non-dehiscent non-dehiscent
(ii) Fruit type legumes (pod) berry hesperidation drupe capsule
(iii) edible or non-edible edible edible edible non-edible
Non edible
(iv) Mode of seed seed seed seed seed
Propagation
(v) Placentaion marginal axial free central basal marginal
(vi) Botanical or caesalpima psidium citrus sp mangifera hibiscus
Scientific name pulchenima guajava indica esculentus
(C)
Specimens mode of dispersal one reason
m explosive mechanism it is a dry dehiscent fruit
n man / animal /water it is a fleshy pericarp with many seeds o man / animal /water same as in N above
p man / animal /water it is light in appearance and easy to carry
q explosive mechanism it is a dry deliscent fruit with many seeds
(D) five conditions are
(i) viability of seed
(ii) suitable temperature
(iii) water
(iv) air
(v) energy
(vi) enzymes
Thanks for viewing.
ReplyDeleteI'm sry for not sending Chemistry answers to you today. I mean the subscribers. I'm very sorry i need not send the Chemistry praticals to you as discussed. I was very busy making regularities for next week. I tot you might not need much due to the chemistry post.
ReplyDeleteI'm very sorry. But that will not come up again, it was b'cous i have to be sure next week stands.
Go and study and practice the diagram of the specimen below
ReplyDeleteAn outer/external structure of specimen J
Longitudinal/vertical section of sp. M
Transverse section of specimen O
Longitudinal/vertical section of sp. P
Transverse section of specimen P
I need comments plz
ReplyDeleteThank u so much 4 ur assistance
ReplyDeletethank you very much... when i first saw ur chemistry, it was different from others that were posted on other websites and so i thought it wasn't genuine, I practised it and similar questions and so it was for biology, I am rilly grateful... please don't forget to help us for math chemistry and physics next week. Thank you.
ReplyDelete